Hello,

I need to find a way to draw this (image attached) asymptote as accurately as possible, preferably in a shape layer.

Not really the expression type, pretty basic. This was my first attempt:

In Path of Shape Layers:

t=value[1];

n=value[14];

x= Math.cos(n*t)/t+t;

y=Math.sin(n*t)/t+t;

[x,y]

I will continue trying to figure out a solution in the meantime, but if someone can easily show me how this can be done directly in a shape layer, I'll owe you one.

Thanks

`t=value[1];`

n=value[14];

x= Math.cos(n*t)/t+t;

y=Math.sin(n*t)/t+t;

[x,y]